After 40 years the coverup continues. In 1977, the House Select Committee on Assassinations came to the conclusion that BOTH the JFK and MLK murders were conspiracies. But the corrupt media won't accept it. For shame, ABC!
This analysis has been previously posted. But for those who have not seen it, here goes....
Take the tinfoil hats off, put your thinking caps on..
This is an analysis to compute the probability of at least 15 witnesses dying UNNATURAL deaths within one year of the JFK assassination. The deaths were a combination of homicides, suicides, accidents and undetermined origin.
Assuming there were 1000 witnesses, the probability that at least 15 would die UNNATURAL deaths in the year following the assassination is: 1 out of 21,230,606,601,227,800.
(or 1 out of 21,230 trillion, 606 billion, 601 million, 227 thousand, 800)
This result is the same order of magnitude of a famous prior, though slightly different, study: An actuary engaged by the London Times in 1963 computed the probability that 18 material witnesses would die (of any cause) within 3 years of the assassination as: 1 out of one hundred thousand trillion.
For the mystery deaths, I used this table, which is no longer active:
http://www.noage.com/jfknetwork/death.htm Here is another link:
http://www.jfk-assassination.de/deaths.htmlFor the odds of death in each category, I used this table of 1999 mortality data:
http://www.nsc.org/lrs/statinfo/odds.htm From the 1999 data:
........................1 year...Lifetime
Probability of:
suicide.................0.000107 0.008197
homicide................0.000062 0.004739
accidental death........0.000359 0.027778
undetermined death......0.000014 0.001101
Therefore, the probability of an unnatural death is the sum of the probabilties of the four categories:
........................0.000542 0.041815
The Poisson Distribution
Although the Normal (Gaussian) probability distribution is by far the most important, there is another which has proven to be particularly useful - the Poisson Distribution, which is derived from, and is a special case of the Normal Distribution.
The Poisson Distribution applies when the probability "P" for success in any one trial is very small, but the number of trials N is so large that the expected number of successes, pN, is a moderate sized quantity. The formula is: P(m) =a**m*exp(-a)/m!
In words, the Probability of EXACTLY m successes = a to the m'th power times the exponential function of (-a), all divided by m factorial.
If m= 15, m factorial = m! = 15*14*13*12*11*10*9*8*7*6*5*4*3*2*1
Now lets use Poisson to determine the probability of a given number of witnesses meeting unnatural deaths within a year of the JFK assassination.
The only assumption we are making here is the number of witnesses.
Assume N= total witnesses = 1000
Let p= Probability of any individual dying from UNNATURAL causes within a given year = 0.000542
Let a= Expected Number of deaths = pN= 0.542
Let m= Actual Number of UNNATURAL deaths = 15
The probability of exactly m=15 UNNATURAL deaths within a given year out of a predefined group of N = 1000 witnesses is:
P(m) =a**m*exp(-a)/m! or p(15)= 0.542**15*exp(-.542)/15!
Here are the probabilities for m=1 through m=15 deaths.
Note:
Prob(X=m) = probability of EXACTLY m DEATHS
Prob(X>=m) = probability of at AT LEAST m DEATHS (the one we want)
m.......Prob(X=m)........Prob(X>=m)
1 3.15E-01 4.18E-01
Thus, for 1 or more deaths, Prob (X>=1)= 0.418
2 8.54E-02 1.03E-01
3 1.54E-02 1.78E-02
4 2.09E-03 2.34E-03
5 2.27E-04 2.49E-04
6 2.05E-05 2.22E-05
7 1.59E-06 1.70E-06
8 1.07E-07 1.14E-07
9 6.47E-09 6.84E-09
10 3.51E-10 3.69E-10
11 1.73E-11 1.81E-11
12 7.80E-13 8.14E-13
13 3.25E-14 3.38E-14
14 1.26E-15 1.31E-15
15 4.55E-17 4.71E-17
For 15 or more deaths,
Prob (X>=15) = 0.000000000000000047101810079330
or 1 out of 21,230,606,601,227,800
Not too likely that these deaths were mere coincidences.
What if there were more than 1000 witnesses? That's a fair question. Well, of course the probabilities will be lower (more likely to occur).
For example, if we assume 5000 witnesses, the probability of 15 deaths is 0.000000190, or 1 out of 5,239,859
column 1 refers to n, the number of deaths,
column 2 is the probability of at least n deaths,
columm 3 is the mathematical odds
Note: the years in which investigations occurred, 1964 and 1977, had the most deaths, 14 and 15. A coincidence?
1000 witnesses
n.......prob.................1 out of
1 0.418 2.39
2 0.103 9.69
3 0.0177 56.26 (1971)
4 0.0023 427 (1968,1975)
5 0.0002 484,018 (1970,74,76)
6 0.000022 45,091 (1967,1969)
7 0.00000169 588,306
8 0.000000114 8,752,118
9 0.00000000683 146,245,847 (1965)
10 0.000000000368 2,712,122,977
11 0.0000000000180 55,278,020,364
12 0.000000000000814 1,228,276,488,499 (1966)
13 0.0000000000000338 29,551,271,527,958
14 0.00000000000000130 765,351,111,903,523 (1967)
15 0.00000000000000004710 21,230,606,601,227,800 (1964)
2000 witnesses
n.......prob...........1 out of
1 .661 1.51
2 0.295 3.39
3 0.096 10.38
4 0.024 41
5 0.005 195
6 0.00089 1,113
7 0.000136 7,343
8 0.0000181 55,093
9 0.00000215 463,452
10 0.000000231 4,321,227
11 0.0000000226 44,239,588
12 0.00000000202 493,399,077
13 0.000000000167 5,954,899,756
14 0.0000000000129 77,331,852,139
15 00000000000093 1,075,228,365,705
5000 witnesses
n........prob............1 out of
1 0.933
2 .753 1.33
3 .508 1.97
4 0.288 3.47
5 0.138 7
6 .057 17
7 0.020 47
8 .00670 148
9 .00196 510
10 .00051 1,939
11 0.00012 8,070
12 0.000027 36,485
13 0.0000056 178,135
14 0.0000010 934,300
15 0.000000190 5,239,859
The House Select Committee on Assassinations could not let the actuary's results stand; it was circumstantial proof of a conspiracy.
In response to a letter from the Committee, "London Sunday Times" Legal Manager Anthony Whitaker stated:
"Our piece about the odds against the deaths of the Kennedy witnesses was, I regret to say, based on a careless journalistic mistake and should not have been published. This was realized by The Sunday Times editorial staff after the first edition - the one which goes to the United States...- had gone out, and later editions were amended. There was no question of our actuary having got his answer wrong: it was simply that we asked him the wrong question. He was asked what were the odds against 15 named people out of the population of the United States dying within a short period of time, to which he replied -correctly - that they were very high. However, if one asks what are the odds against 15 of those included in the Warren Commission Index dying within a given period, the answer is, of course, that they are much lower. Our mistake was to treat the reply to the former question as if it dealt with the latter - hence the fundamental error in our first edition report, for which we apologize".
Here is the fallacy of this obfuscation:
My calculations agree with the original study; and the probabilities are virtually the same (in the trillions). It is a fairly simple calculation - using the Poisson formula. I do not know what formula the actuary used, but it may well have been the Poisson or the Cumulative Normal Distribution.
In any case, the actuary did exactly what he was asked to do. The Times is using Orwellian-speak to give the impression that there was a mistake in the question to be solved. This is total obfuscation. There was NO miscommunication, here's why:
The probability that at least 15 people in the United States (pop. 280 million) would meet violent deaths in any given year is 100%. It is a certainty. On the other hand the probability that 15 out of a population of say, 1000, would do so is infinitesmal, as both my analysis and the actuarial study both prove.
This settled the matter for the House Committee, which apparently made little or no attempt to seriously study the number of mysterious witness deaths which followed the JFK assassination.