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It will be a long, long time before we know.
It seems as if the water in 1 just goes straight into the containment and from there straight somewhere else. I'm relying on TEPCO's statements in saying that - they keep claiming that there's not much water in the reactor vessel and not much in the containment vessel. This implies kind of big holes and not just the minor seal leaks most were expecting.
Following the KISS principle, it does seem most likely that the same cause produced these very big leaks.
The reasons I suspect he is right are several: First, there are relatively low levels of radiation on most of the second floor. This implies that most of the water is going down. If it was steaming off and going up, you'd expect the second floor to be damned hot.
Second, early on they should have been dealing with much hotter fuel, yet they were able to inject less water. The temps started rising in these reactors, and they had to increase injection rates. For example, on April 28th they increased from six tons an hour to 10 tons an hour. Now, it appears that the reactor vessel is leaking at least six-eight tons an hour of water. That's a lot. It's flowing out of the containment vessel nearly as fast, or perhaps even faster.
I am sure they are using metric tons, so 1,000 kilograms, so 2,204 pounds each ton, or about 275 gallons per ton, so the pressure vessel is clearing about 1,650 - 2,200 gallons of water an hour, say 30 gallons a minute. That's a very substantial aperture; it's as if you filled up your bathtub, then opened the drain, and it drained in a minute. That would be a pretty big pipe! Since they say there is almost no water in the vessel, and that the fuel is on the bottom head, we know the water is not flowing out of the pipes up above that head.
It seems as if 3 is now moving into the increased temperature cycle; I am sure that occurs because the flow rate through the vessel increases, which apparently means that the hole or holes at the bottom gets bigger.
There are a few things we know. First, the flow is going to be turbulent, because TEPCO said the reason they thought there was water in there was that the water sensor was pressured by steam. So as water is injected, a considerable portion of it flashes into steam, rises up, condenses, and runs back down. It's pressured.
The equation for non-turbulent water flow is: Flow rate =(Pi (radius^4) (Pressure1 - Pressure2))/(8*Viscosity*Length)
Turbulence might slow flow; we can assume that the length is 2-4 inches, I'm not sure what the viscosity of boiling water is but it is probably between .3 & .6, and I would guess that Pressure1 is greater than Pressure2.
Maybe an engineer will show up to save us. Calling all engineers!
The problem is that the hole will not be round. Assuming low viscosity, that shouldn't matter much. Somewhere around 2.5 inches if it were round. The whole idea that there are tiny leaks/cracks doesn't really make sense (although there should be from seal degradation), because with hot, very thick metal you would expect water running in there to be flashed into steam, thus exerting pressure back out, admittedly on both ends but more so on the inner end. No, it has to be a relatively big hole to get flow rates like that.
It could be a jagged hole four or five inches around!
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